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-5x^2-5x+10=6x-2
We move all terms to the left:
-5x^2-5x+10-(6x-2)=0
We get rid of parentheses
-5x^2-5x-6x+2+10=0
We add all the numbers together, and all the variables
-5x^2-11x+12=0
a = -5; b = -11; c = +12;
Δ = b2-4ac
Δ = -112-4·(-5)·12
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-19}{2*-5}=\frac{-8}{-10} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+19}{2*-5}=\frac{30}{-10} =-3 $
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